segiempat ABCD dan AEFG sebangun. panjang AD adalah ... cm
a. 14
b. 12
c. 10
d. 8
a. 14
b. 12
c. 10
d. 8
AG = √10²- (12-6)² = 8
AD/AG = BC/EF
AD/8 = 15/10
10AD = 120
AD = 12
[answer.2.content]
AG = √10²- (12-6)² = 8
AD/AG = BC/EF
AD/8 = 15/10
10AD = 120
AD = 12
[answer.2.content]