hasil dari :
4/2√5
4/√8-√5
√8+√5/√8-√5
2/√6
NOMOR 1.
[tex]\frac{4}{2 \sqrt{5}} = \frac{2}{\sqrt{5}} = \frac{2}{\sqrt{5}} \times \frac{\sqrt{5}}{\sqrt{5}} = \frac{2 \sqrt{5}}{\sqrt{25}} = \frac{2 \sqrt{5}}{5} [/tex]
NOMOR 2.
[tex]\frac{4}{\sqrt{8} - \sqrt{5}} = \frac{4}{\sqrt{4 \times 2} - \sqrt{5}} = \frac{4}{2 \sqrt{2} - \sqrt{5}} [/tex]
[tex]= \frac{4}{2 \sqrt{2} - \sqrt{5}} \times \frac{2 \sqrt{2} + \sqrt{5}}{2 \sqrt{2} + \sqrt{5}}[/tex]
[tex]= \frac{(4)(2 \sqrt{2} + \sqrt{5})}{(2 \sqrt{2} - \sqrt{5})(2 \sqrt{2} + \sqrt{5})} [/tex]
[tex]= \frac{8 \sqrt{2} + 4 \sqrt{5}}{4 \sqrt{4} + 2 \sqrt{10} - 2 \sqrt{10} - \sqrt{25}} [/tex]
[tex]= \frac{8 \sqrt{2} + 4 \sqrt{5}}{4 \sqrt{4} - \sqrt{25}} = \frac{8 \sqrt{2} + 4 \sqrt{5}}{4 \times 2 - 5} = \frac{8 \sqrt{2} + 4 \sqrt{5}}{8 - 5} = \frac{8 \sqrt{2} + 4 \sqrt{5}}{3}[/tex]
NOMOR 3.
[tex]\frac{\sqrt{8} + \sqrt{5}}{\sqrt{8} - \sqrt{5}} = \frac{\sqrt{4 \times 2} + \sqrt{5}}{\sqrt{4 \times 2} - \sqrt{5}} = \frac{2 \sqrt{2} + \sqrt{5}}{2 \sqrt{2} - \sqrt{5}} [/tex]
[tex]= \frac{2 \sqrt{2} + \sqrt{5}}{2 \sqrt{2} - \sqrt{5}} \times \frac{2 \sqrt{2} + \sqrt{5}}{2 \sqrt{2} + \sqrt{5}} [/tex]
[tex]= \frac{(2 \sqrt{2} + \sqrt{5})(2 \sqrt{2} + \sqrt{5})}{(2 \sqrt{2} - \sqrt{5})(2 \sqrt{2} + \sqrt{5})} [/tex]
[tex]= \frac{4 \sqrt{4} + 2 \sqrt{10} + 2 \sqrt{10} + \sqrt{25}}{4 \sqrt{4} + 2 \sqrt{10} - 2 \sqrt{10} - \sqrt{25}} [/tex]
[tex]= \frac{4 \sqrt{4} + (2 + 2) \sqrt{10} + \sqrt{25} }{4 \sqrt{4} - \sqrt{25}} [/tex]
[tex]= \frac{4 \times 2 + 4 \sqrt{10} + 5}{4 \times 2 - 5} = \frac{8 + 5 + 4 \sqrt{10}}{8 - 5} = \frac{13 + 4 \sqrt{10}}{3} [/tex]
NOMOR 4.
[tex]\frac{2}{\sqrt{6}} = \frac{2}{\sqrt{6}} \times \frac{\sqrt{6}}{\sqrt{6}} = \frac{2 \sqrt{6}}{\sqrt{36}} = \frac{2 \sqrt{6}}{6} = \frac{1 \sqrt{6}}{3} = \frac{\sqrt{6}}{3} [/tex]
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